Mathematics
jwwill14
9

Can someone show me how to solve: 3/5 (y - 2) = (1/4) y + 5

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(2) Answers
ButterKing

If that is: (3/5)(y-2)=(1/4)(y+5) perform indicated multiplications on both sides... (3y-6)/5=(y+5)/4  multiply both sides by 5 3y-6=(5y+25)/4  multiply both sides by 4 12y-24=5y+25 add 24 to both sides 12y=5y+49  subtract 5y from both sides 7y=49  divide both sides by 7 y=7

barchini47

3/5(y-2)=(1/4)y+5 Use distributive property for 3/5(y-2) [latex](3/5*y)-(3/5*2)=1/4y+5[/latex] [latex]3/5y-6/5=1/4y+5[/latex] Subtract 1/4y to each side [latex]3/5y-6/5-1/4y=1/4y+5-1/4y[/latex] [latex]7/20y-6/5=5[/latex] Add 6/5 to each side [latex]7/20y-6/5+6/5=5+6/5 [/latex] [latex]7/20y=25/5+6/5[/latex] [latex]7/20y=31/5 [/latex] Multiply 20/7 to each side [latex]7/20y(20/7)=31/5(20/7)[/latex] [latex]y=620/35=124/7[/latex] y=17 5/7. As a result, y=17 5/7 if that says 3/5(y-20)=(1/4)y+5. Hope it help!

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